3x^2-36x+110=2

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Solution for 3x^2-36x+110=2 equation: 



3x^2-36x+110=2

We move all terms to the left:

3x^2-36x+110-(2)=0

We add all the numbers together, and all the variables

3x^2-36x+108=0

a = 3; b = -36; c = +108;
Δ = b2-4ac
Δ = -362-4·3·108
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{36}{6}=6$

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